How to search from an XML column in SQL

Search from an xml column in sql

<ArticlePage>
  <publishDate><![CDATA[201612151611499007]]></publishDate>
  <category><![CDATA[1000004]]></category>
</ArticlePage>
SELECT *
  FROM [Table_Name]
  where CAST([xml] as XML).value ('(/ArticlePage/category)[1]', 'varchar(max)') like '1000004'

Date Formats in SQL Server

SELECT CONVERT(VARCHAR,GETDATE(),103)

1) SELECT CONVERT(VARCHAR,GETDATE(),100)

Result
May 13 2012 11:30AM

2) SELECT CONVERT(VARCHAR,GETDATE(),101)

Result
05/13/2012

3) SELECT CONVERT(VARCHAR,GETDATE(),102)

Result
2012.05.13

4) SELECT CONVERT(VARCHAR,GETDATE(),103)

Result
13/05/2012

5) SELECT CONVERT(VARCHAR,GETDATE(),104)

Result
13.05.2012

6) SELECT CONVERT(VARCHAR,GETDATE(),105)

Result
13-05-2012

7) SELECT CONVERT(VARCHAR,GETDATE(),106)

Result
13 May 2012

8) SELECT CONVERT(VARCHAR,GETDATE(),107)

Result
May 13, 2012

9) SELECT CONVERT(VARCHAR,GETDATE(),108)

Result
11:41:51

10) SELECT CONVERT(VARCHAR,GETDATE(),109)

Result
May 13 2012 11:43:04:267AM

11) SELECT CONVERT(VARCHAR,GETDATE(),110)

Result
05-13-2012

12) SELECT CONVERT(VARCHAR,GETDATE(),111)

Result
2012/05/13

13) SELECT CONVERT(VARCHAR,GETDATE(),112)

Result
20120513

14) SELECT CONVERT(VARCHAR,GETDATE(),113)

Result
13 May 2012 11:50:02:510

15) SELECT CONVERT(VARCHAR,GETDATE(),114)

Result
11:51:00:330

16) SELECT CONVERT(VARCHAR,GETutcDATE(),114)

Result
06:21:55:597

And if you are looking for a SQL query to find the SQL version, then try this

select @@version

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Get all URLs in Umbraco using SQL

Use the below SQL script to get all the Urls in your Umbraco project

Use the below SQL script to get all the Urls in your Umbraco project.

; WITH PathXml AS (

/* -- This gives nodes with their 'urlName' property
 -- not in recycle bin,
 -- level &amp;amp;amp;amp;gt; 1 which excludes the top level documents which are not included in the url */
 SELECT
 nodeId,
 cast([xml] as xml).query('data(//@urlName[1])').value('.', 'varchar(max)') AS Path
 FROM cmsContentXml x
 JOIN umbracoNode n ON x.nodeId = n.id AND n.trashed = 0 AND n.level > 1
)

SELECT
 u.id,
 u.path,
 '/' +
 /* This is to get the top level document */
 IsNull((SELECT
 pl.Path + '/'
 FROM PathXml pl
 WHERE ',' + u.path + ',' LIKE '%,' + CAST(pl.nodeId AS VARCHAR(MAX)) + ',%'
 ORDER BY CHARINDEX(',' + CAST(pl.nodeId AS VARCHAR(MAX)) + ',',
 ',' + u.path + ',')

FOR XML PATH('')),
 '') AS Url,
 u.text PageName
FROM umbracoNode u
WHERE nodeObjectType = 'C66BA18E-EAF3-4CFF-8A22-41B16D66A972' /* Document node */
AND trashed = 0
ORDER BY 3 /* Url */


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